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Given that a kg of copper contains about 10^25 atoms and that the density of copper is about 9000kg/m^3.estimate the diameter of the copper atoms?State...

Given that a kg of copper contains about 10^25 atoms and that the density of copper is about 9000kg/m^3. Estimate the diameter of the copper atoms?
State the assumption made.

Answers

Alphonce
Density= mass/ volume
9000kg/m3= 1kg/ volume
Volume=1/9000 m3
Volume of atom is given as 4/3pr3
Hence 1/9000m3=4/3pr3
R=582.4878(for10^25 atoms)
For one atom =582.4878/10^25
= 5.824878×10^-23
Hence diameter= 1.165×10^-22
Assumptions here is that the atoms are spherical
Alphonce100 answered the question on June 15, 2018 at 03:43

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